![]() ![]() Now: the mv command can and does work on multiple files. Mkdir: cannot create directory ‘file2.txt’: File exists Mkdir: cannot create directory ‘file1.txt’: File exists The expansion can further be viewed if you do, for example: $ ls By quoting you prevent the wildcards from being expanded if there should be any matches. Now: using commands like some_command *.tsv when the intention is to actually keep the wildcard one should always quote it. $ mv *1.txt *.tsvĪs *.tsv now is a directory, the files end up being moved there. That is: the file is renamed to *.tsv with the asterisk and all. As it does not, the file file1.txt is moved to *.tsv. Now, again, mv checks to see if *.tsv exists. The mv command is executed with: argc = 3 Now if you instead say: $ mv *1.txt *.tsv (combine all the files into one.) Nor can it create directories on a whim.Īs a result, it aborts and reports the error: mv: target ‘*.tsv’ is not a directory As it is not, the program can not continue as it is not designed to concatenate files. The mv program checks to see if the last argument, *.tsv, is a directory. In the above example that would be: argc = 4 argv: An array of arguments, including the program as first entry.argc: Number of arguments, including the program.The mv command is called with two special arguments: As there are no *.tsv files that is not changed. Now what happens on the mv line is that the shell expands *.txt to the matching files. ![]() Loads of examples is perhaps best way to understand why this won't work. If no matches are found the unexpanded version is passed.Īgain: the shell expands the patterns, not the program. The list of files is passed to the program, here mv. The shell, lets assume bash, expands the wildcards if there are any matching files (including directories). When you issue the command: mv *.txt *.tsv This answer won't help you change the extension, but it will help you understand why your command is not doing what you expect. 1 root root 0 Jan 26 11:40 test4.gappedPeak 1 root root 0 Jan 26 11:40 test3.gappedPeak 1 root root 0 Jan 26 11:40 test2.gappedPeak 1 root root 0 Jan 26 11:40 test1.gappedPeak name "*.gappedPeak" -exec sh -c 'mv "$1" "$ is replaced by each ( *.gappedPeak) filename foundīy the find command, and becomes $1 to the sh command. This should work on any POSIX-compliant system: find. I know this doesn't answer your question, but in case you were looking for another way to rename the files compared to your work-around loop, why not use find? I have used this command many times to replace file extensions in large directories with hundreds of thousands of files in it. For more information on bash scripting you may like to see the advanced bash scripting guide, authored by Mendel Cooper. The above script renames files using a built-in bash function. The next portion of the line removes the JPG extension from the end and adds the jpg extention to each file. The '$i' is a string containing the name of the file that matches. The second line uses basename (type man basename for more details) with the '$i' argument. The first line says find everything with the “.JPG” extension (capitals only, because the UNIX system is case sensitive). Unfortunately I do not know the author's name. Note that the above script came from a usenet post. One way to this is shown below: for i in *.JPG Scripts are useful if you don't have mmv or rename. You can develop a set of instructions (a script) to rename files. I would recommend trying CPAN Search Site, I found the script here Rename Script Version 1.4 Bash scriptingīash scripting is one way to rename files. Finding rename: You can get rename from various places. ![]()
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